# E-capture (Gerhard Hunf)

The following post has been submitted by Gerhard Hunf

“E-capture”

In “ http://www.e-catworld.com/2016/11/15/high-current-densities-environmental-conditions-for-cold-fusion-gerhard-hunf/ “ was shown, the current flow at the contact point (conductor / superconductor) is almost completely changed from the conductor to the superconductor. For this, the velocity of the electrons must change in the ratio of the cross sections mm2 / nm2 (conductor / superconductor). The branching point (conductor / superconductor) thus acts as a particle accelerator for electrons. The electron becomes heavier.

The “e-capture reaction” can be formulated as follows
(p + + e) + E1 = n + v.

E1 can be calculated from the mass difference Δm = m (neutron) – m (p + + e). The mass difference is 1.39 x 10exp-30 kg. Substituting this into E mc2 gives E1 = 1.249x10exp-13J or 0.78MeV.

This work W = U I t. must be supplied by the system. In order to check whether a current density (J) of 10exp11 A / m2 is sufficient, we use for the superconducting layer
W = U I t = U x (J x F) x s / v => J = W x v / U x F x s

W = 1.249×10-exp-13J; v = 10exp2 m / sec; U = 12V (battery); F = 10exp-12 m2; s = 10exp-10 m. ! Attention: 1Volt is also 1J/C, 1Ampere is also 1C/sec!

From this follows current density (J) is about 10exp11 A / m2

This means current density for the “e-capture” is the same achieved in the superconducting layer.

Gerhard Hunf

## 10 Replies to “E-capture (Gerhard Hunf)”

1. Andreas Moraitis says:

Don’t we have to assume Cooper-pairs here instead of ‘classical’ conduction electrons? If so, which consequences would you see both with regard to the energy aspect and the supposed mechanism of electron capture?

1. hunfgerh says:

Yes and no.
The quantum-mechanical calculation of the current density to the one performed
here will less differ. However, the current density is only a measure for the
number of charge carriers.

But the mechanism of “e-capture” can only be carried out if the cooper-pair
(spin 0) decouples after a certain coherent length 10exp-6m -10exp-10m into two
uncoupeld electrons with the (spin ½) in the same direction. “Superconducting
is a periodic decoupl/ coupel process.” For this reason, the same number of unpaired electrons are present in a superconductor in addition to the cooper pairs. Only by this can the s-electronbe pushed into the core by repulsion of similar charges.

2. Alan DeAngelis says:

I thought you might find this interesting Gerhard. A few weeks after the F&P announcement Larry A Hull (in a letter to Chemical and Engineering News, May 15, 1989, page 3) proposed the mechanism of a deuteron capturing an electron to become nn, “dineutronium”.

http://disq.us/p/v91dbc

1. hunfgerh says:

The question here and there,

From where comes Δm. And how can it transformed into practice
under the conditions of P @ F. This question is to answer.

1. Alan DeAngelis says:

Yes, I agree and it does not explain deuterium gas with palladium systems like Les Chase’s “football” (36:36 min.) that produced helium (mass spectrum at 37:05).

2. Da Phys says:

Here is the DOI:
10.1021/cen-v067n020.p002
The letter is available on sci-hub. Nice read. Shows how people reacted a few weeks after F&P announcement.

1. Alan DeAngelis says:

Yeah, and there’s a letter from a crackpot named DeAngelis just above Hull’s letter.

1. Alan DeAngelis says:

Now (27 years later) I’m thinking that the palladium of palladium hydride, D2Pd during symmetric IR stretching could fuse with its deuterons to form cadmium in an excited state, Cd* that in turn would fission back into palladium and helium.

D~Pd~D > Cd* > Pd + He 24 MeV

Maybe some Boscovichian physics might come into play here.

http://www.mifami.org/eLibrary/BoscoCurve.jpg

1. Alan DeAngelis says: